Which element has the electron configuration [Xe] 6s2 4f14 5d10 6p2?

A. gold (atomic number 79)

B. mercury (atomic number 80)

C. lead (atomic number 82)

D. potassium (atomic number 19)

E. copper (atomic number 29)

3 Answers

  • Sayden
    9 days ago

    C. Lead

    Lead, Pb(82): Shells: (K,L,M, N, O, P) = 1st -6th period electron ‘shells’ 2,8,18,32,18,4 = total 82 electrons

    orbitals: ordered by main quantum number 1 – 6, separated by comma’s 1s 2 , 2s 2 2p 6 , 3s 2 3p 6 3d 10 , 4s 2 4p 6 4d 10 4f 14 , 5s 2 5p 6 5d 10 , 6s 2 6p 2

  • nasser
    4 days ago

    you’re to apply the noble gas on the line above the ingredient which you’re doing the configuration for. consequently, utilising only any ingredient could be incorrect. Noble gases are used because of the fact their shells are finished. because of the fact their shells are finished, they can’t benefit anymore electrons. they’re sturdy components. while utilising the noble gas listed till now the ingredient, that noble gas because of the fact the comparable electron configurations each and every time. consequently, utilising that to initiate with yields the precise comparable commencing up each and every time because of the fact it can’t have a distinctive one. i’m hoping that facilitates! I hated chemistry in college….blah!

  • drown
    4 days ago

    Xe 6s2 4f14 5d10 6p2

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