Please Help?

1 Answer

• Lopez

  4 days ago

  Suppose X defects occur, then X ~ Poisson distribution.

  p(x)

  = λ^x * e^(-λ) / x!

  = 0.1^x * e^(-0.1) / x!

  P( X ≧ 1 )

  = 1 – P( X < 1 )

  = 1 – P(0)

  = 1 – e^(-0.1)

  ≒ 0.095 ….. Ans

  0