Physics Question HELP!!!?

2 Answers

• ?

  5 days ago

  Since the arrow and apple are at the same height, use the range equation:

  x = V²sin(2Θ) / g

  28.0 m = (31.8m/s)²sin(2Θ) / 9.8m/s²

  sin(2Θ) = 0.271

  2Θ = 15.7º

  Θ = 7.87º

  If you find this helpful, please award Best Answer!

  1
• Vaman

  5 days ago

  When the arrow moves through the air it is pulled down by the gravity. This should be corrected. Let v be the horizontal velocity. The time taken by the arrow to reach 28 m is 28/v. In this it falls through the distance

  s = 1/2 g t^2= 1/2 g (28/v)^2.

  s and horizontal direction make a right angled triangle. Therefore, the angle theta must be

  tan theta = g/2 28^2/v^2 /28

  Put the values

  tan theta=0.136

  theta= 7.745 degrees above the horizontal direction.

  0