How to balance NH3 (g) + O2 (g) + CH4 (g) –> HCN (aq) + H2O (l)?

2 Answers

• Anonymous

  1 month ago

  You want the # of atoms on each side to be equal.

  I would first start with guessing that there is 1 NH3,

  therefore there must be 1 HCN.

  1 C on left side means that there must be

  1 CH4 (only source of C on right side),

  This means there are 7 H’s on the left.

  1 NH3 = 3 H

  1 CH4 = 4 H

  we have 1 on the right (from HCN)

  so that means there are 6 more in

  H20 (the only other source of H on the right side)

  That means 3 H20.

  Now we have 3 0’s on the right,

  3 H20 = 3 0

  we need 3 0’s on the left.

  Since 0 only comes in 02,

  we should multply all of our previous guesses by 2,

  (in order to have 6 0’s on the right, 3 02 = 6 0

  so we have:

  2 NH3 + x 02 + 2 CH4 = 2 HCN + 6 H20

  now we see that we need 6 0’s on the left, or 3 02’s

  2 NH3 + 3 02 + 2 CH4 = 2 HCN + 6 H20

  Check your answer by making sure there are an equal number of each atom on each side.

  1
• mastro

  4 days ago

  Ch4 Nh3

  0