how much tension must a rope withstand if it is used to accelerate a 960kg car horizontally along a………..?

frictionless surface at 1.20 m/s2

please help!!!!!!!!

1 Answer

  • Algol
    1 month ago

    This is Newton’s 2nd law. Just replace F with T:

    T = ma

    = 960kg x 1.20m/s^2

    = 1152N

    Hope this helps.

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