How many grams of solute are needed to prepare 2.00L of a 1.50 M NaOH solution?

4 Answers

• Utsjal

  10 hours ago

  We have,

  Molarity = No. of moles/ Vol. of solute in liter

  1.50 = (Wt. in gram/ Molecular wt) / volume of solute

  1.5 = (Wt. in gram / 41 ) / 2

  Thus, Wt in gram = 1.5 * 41 * 2 = 123 gm.

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• bogert

  4 days ago

  you pick 0.one hundred seventy five L of a concentration of three.0 M. considering C = n / V you will discover “n” (moles) in the answer by using multiplying C x V n = 3 M x 0.one hundred seventy five L = 0.525 moles of NaOH in the answer. Now convert that many moles of NaOH right into a mass mass = moles x Molar mass mass = 0.525 moles x 40.00 g/mol = 21 g

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• ?

  10 hours ago

  The formula is M=moles/liter

  moles = M*liter

  =1.50M (2.00L)

  =3 moles

  molar mass = 40g/moles

  So, 40g/moles(3moles) = 120 grams

  1
• Anonymous

  10 hours ago

  1.5 M solution means that you have 1.5 moles of NaOH per Litre

  you are making 2 L here so you must have 1.5*2=3 moles

  G.M.M. of NaOH is 40 gms i.e. 1 mole of NaOH has mass of 40 gms

  you require 3 moles so 40*3=120 gms

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