# How many grams of solute are needed to prepare 2.00L of a 1.50 M NaOH solution?

• Utsjal
10 hours ago

We have,

Molarity = No. of moles/ Vol. of solute in liter

1.50 = (Wt. in gram/ Molecular wt) / volume of solute

1.5 = (Wt. in gram / 41 ) / 2

Thus, Wt in gram = 1.5 * 41 * 2 = 123 gm.

• bogert
4 days ago

you pick 0.one hundred seventy five L of a concentration of three.0 M. considering C = n / V you will discover “n” (moles) in the answer by using multiplying C x V n = 3 M x 0.one hundred seventy five L = 0.525 moles of NaOH in the answer. Now convert that many moles of NaOH right into a mass mass = moles x Molar mass mass = 0.525 moles x 40.00 g/mol = 21 g

• ?
10 hours ago

The formula is M=moles/liter

moles = M*liter

=1.50M (2.00L)

=3 moles

molar mass = 40g/moles

So, 40g/moles(3moles) = 120 grams

• Anonymous
10 hours ago

1.5 M solution means that you have 1.5 moles of NaOH per Litre

you are making 2 L here so you must have 1.5*2=3 moles

G.M.M. of NaOH is 40 gms i.e. 1 mole of NaOH has mass of 40 gms

you require 3 moles so 40*3=120 gms