For the combination of resistors shown, find the equivalent resistance between points A and B.?

For the combination of resistors shown, find the equivalent resistance between points A and B.

http://session.masteringphysics.com/problemAsset/1…

Its an extra credit problem, but i am struggling with it.

Update:

IM SORRY, I COPIED THE WRONG LINK, I had gotten the answer to that one, this was the one i was struggling with

http://session.masteringphysics.com/problemAsset/1…

IM SORRY, I COPIED THE WRONG LINK, I had gotten the answer to that one, this was the one i was struggling with

http://session.masteringphysics.com/problemAsset/1…

4 Answers

  • Technobuff
    8 days ago

    4, 6 and 12 in parallel 1/r = (1/4 + 1/6 + 1/12) = 2 ohms.

    5 and 20 in parallel = (5 x 20) /(5 + 20), = 4 ohms.

    (1 + 3 + 2) = 6 ohms.

    (2 + 4) = 6 ohms.

    6 and 6 in parallel = 3 ohms between A and B.

  • Dung
    6 days ago

    This Site Might Help You.

    RE:

    For the combination of resistors shown, find the equivalent resistance between points A and B.?

    For the combination of resistors shown, find the equivalent resistance between points A and B.

    http://session.masteringphysics.com/problemAsset/1…

    Its an extra credit problem, but i am struggling with it.

  • billrussell42
    8 days ago

    struggling? really?

    4 and 12 in parallel are equiv to 4•12/16 = 3 ohms

    3 in series with 2 equal 5 ohms

  • Mushtaque Panhwar
    5 days ago

    which formula you use to find the resistance

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