Find the enthalpy of the reaction for: 2SO3(g) –> 2SO2(g) + O2 (g)?

Given:

S(s) + O2 (g) –> SO2 (g) Change in H = -296.8 kJ/mol

S(s) + 3/2 O2 (g) –> SO3 (g) Change in H = -395.6 kJ/mol

1 Answer

  • obama pharmacist
    1 month ago

    2SO2 + O2 —–> 2SO3

    ——— – – – – – – – – – – – – – – – – –

    2SO3 —–> 2S + 3O2 (+395.6 )2

    2S + 2O2 —–> 2SO2 (-296.8)2

    – – – – – – – – – – – – – – – – – – – – – – – net eqxn

    2SO3 ——> 2SO2 + O2 ={+791.2 – 593.6} = +197.6

    Ans= +197.6

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