Find the enthalpy of the reaction for: 2SO3(g) –> 2SO2(g) + O2 (g)? Given: S(s) + O2 (g) –> SO2 (g) Change in H = -296.8 kJ/molS(s) + 3/2 O2 (g) –> SO3 (g) Change in H = -395.6 kJ/mol1 Answer obama pharmacist1 month ago2SO2 + O2 —–> 2SO3——— – – – – – – – – – – – – – – – – – 2SO3 —–> 2S + 3O2 (+395.6 )22S + 2O2 —–> 2SO2 (-296.8)2– – – – – – – – – – – – – – – – – – – – – – – net eqxn2SO3 ——> 2SO2 + O2 ={+791.2 – 593.6} = +197.6Ans= +197.6 0