Find an equation of the plane with x intercept a, y intercept b, and z intercept c. What is the distance between the origin and the plane?
Please show work and explain. Thanks!
1 Answers

Consider that the plane has x intercept a, y intercept b, and z intercept c. So, the point on xaxis is A=(a,0,0) = (21,71,21)
The point on yaxis is B = (0,0,0)=(23,72,22)
The point on zaxis is C=(0,0,0) = (13,73,23) So, the plane passing through the points A, B, Cis,
**1 yyı 221 12  X Y  321 = 0 *3  X Y3> 2321
xa y0201 10a b0 00=o 0a 00 00
xa y z a b 0=0