Find an equation of the plane with x intercept a

1 Answers

• Margherita Kucera

  87 days ago

  

  Consider that the plane has x intercept a, y intercept b, and z intercept c. So, the point on x-axis is A=(a,0,0) = (21,71,21)
  The point on y-axis is B = (0,0,0)=(23,72,22)
  The point on z-axis is C=(0,0,0) = (13,73,23) So, the plane passing through the points A, B, Cis,
  *-*1 y-yı 2-21 12 - X Y - 3-21 = 0 *3 - X Y3-> 23-21
  x-a y-02-01 10-a b-0 0-0=o 0-a 0-0 0-0
  x-a y z -a b 0=0

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