A dioxin-contaminated water source contains 0.085% dioxin by mass. How much dioxin is present in 2.5 L of this water? Assume a density of 1.00 g/mL.

Could someone work this out and explain the steps to me?

### 2 Answers

so this is what you use…you use a little dimensional analysis:

first turn the g/mL to g/L

_1.00g___ x__ 1000mL_ = 1000g/L

mL…………………1 L

now do the rest:

___2.5L dioxin____ x __1000g___= 2500 g dioxin water

……………………………..1 L

but since it’s onli 0.085% by mass…you have to multiply 2500g by 0.00085 (percents are always out of a hundered so when you’re multiplying it to a number you need to divide it by a 100) and this should give you 2.125g

2.125 g