Chemistry problem equation?

A dioxin-contaminated water source contains 0.085% dioxin by mass. How much dioxin is present in 2.5 L of this water? Assume a density of 1.00 g/mL.

Could someone work this out and explain the steps to me?

2 Answers

  • Dr.A
    1 month ago

    2.5 L = 2500 mL

    mass solution = 2500 mL x 1 g/mL = 2500 g

    0.085 % = mass solute 100 / mass solution = mass solute x 100 / 2500

    mass solute = 2500 x 0.085 / 100=2.13 g

  • Anonymous
    1 month ago

    so this is what you use…you use a little dimensional analysis:

    first turn the g/mL to g/L

    _1.00g___ x__ 1000mL_ = 1000g/L

    mL…………………1 L

    now do the rest:

    ___2.5L dioxin____ x __1000g___= 2500 g dioxin water

    ……………………………..1 L

    but since it’s onli 0.085% by mass…you have to multiply 2500g by 0.00085 (percents are always out of a hundered so when you’re multiplying it to a number you need to divide it by a 100) and this should give you 2.125g

    2.125 g

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