An aluminum plate 0.5 cm thick is to withstand a force of 50,000 N

An aluminum plate 0.5 cm thick is to withstand a force of 50,000 N with no permanent deformation. If the aluminum has a yield strength of 125 MPa, what is the minimum width of the plate?

1 Answers

  • Becki Paris
    59 days ago
    An aluminum plate 0.5 cm thick is to withstand

    Calculate the original cross-sectional area of the aluminum plate. Here, force is and yield strength of aluminum is . Substitute 50,000 N for and 125 MPa for .

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