A skier slides horizontally along the snow for a distance of 18 m before coming to rest. The coefficient of ki?

A skier slides horizontally along the snow for a distance of 18 m before coming to rest. The coefficient of kinetic friction between the skier and the snow is μk = 0.030. Initially, how fast was the skier going?

1 Answer

  • Anonymous
    1 month ago

    Work done by snow = µk . m . g . d

    KE lost = 1/2 . m . v^2

    These are the same.

    0.03 . 9.8 . 18 = 1/2 . v^2

    v = 3.25 = 3.3 m/s

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